4.8.1. Exercise: Graphical input

You recorded a force profile using a force sensor at a sampling frequency of 10 Hz. Here are the 44 first samples of this signal:

force = [
    0.37571429, 0.39095238, 0.38333333, 0.37190476, 0.37952381, 0.36809524,
    0.40238095, 0.37571429, 0.37571429, 0.37571429, 0.39857143, 0.36047619,
    0.38333333, 0.36428571, 0.74142857, 0.97      , 0.29952381, 0.41761905,
    0.33380952, 0.38333333, 0.35285714, 0.37571429, 0.36428571, 0.38333333,
    0.36809524, 0.37571429, 0.36428571, 0.37571429, 0.38333333, 0.36047619,
    0.37571429, 0.36047619, 0.37190476, 0.36809524, 0.35285714, 0.35666667,
    0.37190476, 0.38333333, 0.36809524, 0.38333333, 0.36809524, 0.36428571,
    0.37571429, 0.36047619
]
     
time = [
    0. , 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1. , 1.1, 1.2,
    1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2. , 2.1, 2.2, 2.3, 2.4, 2.5,
    2.6, 2.7, 2.8, 2.9, 3. , 3.1, 3.2, 3.3, 3.4, 3.5, 3.6, 3.7, 3.8,
    3.9, 4. , 4.1, 4.2, 4.3
]

This force spike was deliberately generated as a synchronization signal, by gently impacting the force sensor. We need to read the time at which the spike occurs in the signal above.

Instead of reading it approximately on the curve, write this interactive function:

def get_spike_time(time: list[float], force: list[float]) -> float:
    """
    Interactively get spike time by asking a user to click on it.

    This function plots the signal defined by `time` and `force`, then waits
    for the user to click on the spike, and then returns the spike time in
    seconds.

    Parameters
    ----------
    time
        A series of time, in seconds.

    force
        A series of force, that is the same length as `time`, in newtons.

    Returns
    -------
    float
        The time selected by the user, in seconds.

    """

import matplotlib.pyplot as plt

def get_spike_time(time, force):
    plt.plot(time, force)
    points = plt.ginput(1)
    return points[0][0]  # Coordinate 0 (x) of point 0 (1st and only point)